Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1111010111100100011 |
3 | 110112010200212111101211 |
4 | 1322000101322330203 |
5 | 4121242301403134 |
6 | 140103042210551 |
7 | 12315221555005 |
oct | 1720021727443 |
9 | 415120774354 |
10 | 131001200419 |
11 | 506148428a1 |
12 | 21480053a57 |
13 | c47944220b |
14 | 64aa44a375 |
15 | 361abd0764 |
hex | 1e8047af23 |
131001200419 has 2 divisors, whose sum is σ = 131001200420. Its totient is φ = 131001200418.
The previous prime is 131001200387. The next prime is 131001200423. The reversal of 131001200419 is 914002100131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131001200419 - 25 = 131001200387 is a prime.
It is a super-2 number, since 2×1310012004192 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131001200419.
It is not a weakly prime, because it can be changed into another prime (131001200459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500600209 + 65500600210.
It is an arithmetic number, because the mean of its divisors is an integer number (65500600210).
Almost surely, 2131001200419 is an apocalyptic number.
131001200419 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001200419 is an equidigital number, since it uses as much as digits as its factorization.
131001200419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
The spelling of 131001200419 in words is "one hundred thirty-one billion, one million, two hundred thousand, four hundred nineteen".
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