Base | Representation |
---|---|
bin | 11101110010010101000111… |
… | …101011101100010001111001 |
3 | 122011211200001122000220102221 |
4 | 131302111013223230101321 |
5 | 114132314044013144233 |
6 | 1142341253230124041 |
7 | 36410403454250002 |
oct | 3562250753542171 |
9 | 564750048026387 |
10 | 131002000131193 |
11 | 388176aa94a304 |
12 | 12839094950621 |
13 | 58135880429b9 |
14 | 244c7600d61a9 |
15 | 10229e16eb42d |
hex | 772547aec479 |
131002000131193 has 2 divisors, whose sum is σ = 131002000131194. Its totient is φ = 131002000131192.
The previous prime is 131002000131139. The next prime is 131002000131271. The reversal of 131002000131193 is 391131000200131.
Together with previous prime (131002000131139) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 117924027274089 + 13077972857104 = 10859283^2 + 3616348^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131002000131193 is a prime.
It is not a weakly prime, because it can be changed into another prime (131002000131103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501000065596 + 65501000065597.
It is an arithmetic number, because the mean of its divisors is an integer number (65501000065597).
Almost surely, 2131002000131193 is an apocalyptic number.
It is an amenable number.
131002000131193 is a deficient number, since it is larger than the sum of its proper divisors (1).
131002000131193 is an equidigital number, since it uses as much as digits as its factorization.
131002000131193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 131002000131193 in words is "one hundred thirty-one trillion, two billion, one hundred thirty-one thousand, one hundred ninety-three".
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