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1310020031103 = 37507712287159
BaseRepresentation
bin10011000100000011010…
…001110101001001111111
311122020101112210202212020
4103010003101311021333
5132430410111443403
62441452003411223
7163434342352140
oct23040321651177
94566345722766
101310020031103
11465638178933
12191a83083b13
13966c3ca9224
1447596243ac7
152412393d453
hex1310347527f

1310020031103 has 16 divisors (see below), whose sum is σ = 1996614351360. Its totient is φ = 748435368096.

The previous prime is 1310020031083. The next prime is 1310020031143. The reversal of 1310020031103 is 3011300200131.

It is not a de Polignac number, because 1310020031103 - 210 = 1310020030079 is a prime.

It is a super-2 number, since 2×13100200311032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310020031143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6036963 + ... + 6250196.

It is an arithmetic number, because the mean of its divisors is an integer number (124788396960).

Almost surely, 21310020031103 is an apocalyptic number.

1310020031103 is a deficient number, since it is larger than the sum of its proper divisors (686594320257).

1310020031103 is a wasteful number, since it uses less digits than its factorization.

1310020031103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12292246.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1310020031103 its reverse (3011300200131), we get a palindrome (4321320231234).

The spelling of 1310020031103 in words is "one trillion, three hundred ten billion, twenty million, thirty-one thousand, one hundred three".

Divisors: 1 3 7 21 5077 15231 35539 106617 12287159 36861477 86010113 258030339 62381906243 187145718729 436673343701 1310020031103