131002022121 has 4 divisors (see below), whose sum is σ = 174669362832. Its totient is φ = 87334681412.

The previous prime is 131002022119. The next prime is 131002022143. The reversal of 131002022121 is 121220200131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121220200131 = 3 ⋅40406733377.

It is a cyclic number.

It is not a de Polignac number, because 131002022121 - 2¹ = 131002022119 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 131002022121.

It is not an unprimeable number, because it can be changed into a prime (131002022191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21833670351 + ... + 21833670356.

It is an arithmetic number, because the mean of its divisors is an integer number (43667340708).

Almost surely, 2^131002022121 is an apocalyptic number.

It is an amenable number.

131002022121 is a deficient number, since it is larger than the sum of its proper divisors (43667340711).

131002022121 is an equidigital number, since it uses as much as digits as its factorization.

131002022121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43667340710.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 131002022121 its reverse (121220200131), we get a palindrome (252222222252).

The spelling of 131002022121 in words is "one hundred thirty-one billion, two million, twenty-two thousand, one hundred twenty-one".