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13100212431433 = 531155232139607
BaseRepresentation
bin1011111010100010000110…
…0000100010101001001001
31201101100221022212111200001
42332220201200202221021
53204113213340301213
643510053212443001
72521313322251461
oct276504140425111
951340838774601
1013100212431433
1141a0850439766
121576aaa779461
137404634b561a
143340a7382ba1
1517ab773841dd
hexbea21822a49

13100212431433 has 8 divisors (see below), whose sum is σ = 13347508027968. Its totient is φ = 12852921345264.

The previous prime is 13100212431343. The next prime is 13100212431461. The reversal of 13100212431433 is 33413421200131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13100212431433 - 225 = 13100178877001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100212431473) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5052916 + ... + 7192522.

It is an arithmetic number, because the mean of its divisors is an integer number (1668438503496).

Almost surely, 213100212431433 is an apocalyptic number.

It is an amenable number.

13100212431433 is a deficient number, since it is larger than the sum of its proper divisors (247295596535).

13100212431433 is a wasteful number, since it uses less digits than its factorization.

13100212431433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2255183.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13100212431433 its reverse (33413421200131), we get a palindrome (46513633631564).

The spelling of 13100212431433 in words is "thirteen trillion, one hundred billion, two hundred twelve million, four hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 53 115523 2139607 6122719 113399171 247173819461 13100212431433