Base | Representation |
---|---|
bin | 11000011001101010… |
… | …11000101010001001 |
3 | 1020210222101021201122 |
4 | 30030311120222021 |
5 | 203312124114423 |
6 | 10003531125025 |
7 | 642431026205 |
oct | 141465305211 |
9 | 36728337648 |
10 | 13100223113 |
11 | 561280957a |
12 | 26572a3775 |
13 | 130a092c13 |
14 | 8c3bb7b05 |
15 | 51a14c8c8 |
hex | 30cd58a89 |
13100223113 has 16 divisors (see below), whose sum is σ = 14059051200. Its totient is φ = 12168636480.
The previous prime is 13100223107. The next prime is 13100223139. The reversal of 13100223113 is 31132200131.
It is a cyclic number.
It is not a de Polignac number, because 13100223113 - 28 = 13100222857 is a prime.
It is a super-2 number, since 2×131002231132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13100223091 and 13100223100.
It is not an unprimeable number, because it can be changed into a prime (13100223163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2021843 + ... + 2028311.
It is an arithmetic number, because the mean of its divisors is an integer number (878690700).
Almost surely, 213100223113 is an apocalyptic number.
It is an amenable number.
13100223113 is a deficient number, since it is larger than the sum of its proper divisors (958828087).
13100223113 is a wasteful number, since it uses less digits than its factorization.
13100223113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8552.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 13100223113 its reverse (31132200131), we get a palindrome (44232423244).
The spelling of 13100223113 in words is "thirteen billion, one hundred million, two hundred twenty-three thousand, one hundred thirteen".
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