Search a number
-
+
13100223113 = 195320116469
BaseRepresentation
bin11000011001101010…
…11000101010001001
31020210222101021201122
430030311120222021
5203312124114423
610003531125025
7642431026205
oct141465305211
936728337648
1013100223113
11561280957a
1226572a3775
13130a092c13
148c3bb7b05
1551a14c8c8
hex30cd58a89

13100223113 has 16 divisors (see below), whose sum is σ = 14059051200. Its totient is φ = 12168636480.

The previous prime is 13100223107. The next prime is 13100223139. The reversal of 13100223113 is 31132200131.

It is a cyclic number.

It is not a de Polignac number, because 13100223113 - 28 = 13100222857 is a prime.

It is a super-2 number, since 2×131002231132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13100223091 and 13100223100.

It is not an unprimeable number, because it can be changed into a prime (13100223163) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2021843 + ... + 2028311.

It is an arithmetic number, because the mean of its divisors is an integer number (878690700).

Almost surely, 213100223113 is an apocalyptic number.

It is an amenable number.

13100223113 is a deficient number, since it is larger than the sum of its proper divisors (958828087).

13100223113 is a wasteful number, since it uses less digits than its factorization.

13100223113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8552.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13100223113 its reverse (31132200131), we get a palindrome (44232423244).

The spelling of 13100223113 in words is "thirteen billion, one hundred million, two hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 19 53 1007 2011 6469 38209 106583 122911 342857 2025077 6514283 13009159 247174021 689485427 13100223113