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1310030030003 is a prime number
BaseRepresentation
bin10011000100000011110…
…111111110010010110011
311122020102020121202202212
4103010003313332102303
5132430420141430003
62441453002002335
7163434523345352
oct23040367762263
94566366552685
101310030030003
11465642888192
12191a864a63ab
13966c609a436
14475976c7999
1524124765dd8
hex13103dfe4b3

1310030030003 has 2 divisors, whose sum is σ = 1310030030004. Its totient is φ = 1310030030002.

The previous prime is 1310030029963. The next prime is 1310030030021. The reversal of 1310030030003 is 3000300300131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310030030003 - 26 = 1310030029939 is a prime.

It is a super-2 number, since 2×13100300300032 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310030030003.

It is not a weakly prime, because it can be changed into another prime (1310030030033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655015015001 + 655015015002.

It is an arithmetic number, because the mean of its divisors is an integer number (655015015002).

Almost surely, 21310030030003 is an apocalyptic number.

1310030030003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310030030003 is an equidigital number, since it uses as much as digits as its factorization.

1310030030003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 14.

Adding to 1310030030003 its reverse (3000300300131), we get a palindrome (4310330330134).

The spelling of 1310030030003 in words is "one trillion, three hundred ten billion, thirty million, thirty thousand, three".