Base | Representation |
---|---|
bin | 10011000100000011110… |
… | …111111110010010110011 |
3 | 11122020102020121202202212 |
4 | 103010003313332102303 |
5 | 132430420141430003 |
6 | 2441453002002335 |
7 | 163434523345352 |
oct | 23040367762263 |
9 | 4566366552685 |
10 | 1310030030003 |
11 | 465642888192 |
12 | 191a864a63ab |
13 | 966c609a436 |
14 | 475976c7999 |
15 | 24124765dd8 |
hex | 13103dfe4b3 |
1310030030003 has 2 divisors, whose sum is σ = 1310030030004. Its totient is φ = 1310030030002.
The previous prime is 1310030029963. The next prime is 1310030030021. The reversal of 1310030030003 is 3000300300131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310030030003 - 26 = 1310030029939 is a prime.
It is a super-2 number, since 2×13100300300032 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1310030030003.
It is not a weakly prime, because it can be changed into another prime (1310030030033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655015015001 + 655015015002.
It is an arithmetic number, because the mean of its divisors is an integer number (655015015002).
Almost surely, 21310030030003 is an apocalyptic number.
1310030030003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310030030003 is an equidigital number, since it uses as much as digits as its factorization.
1310030030003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 14.
Adding to 1310030030003 its reverse (3000300300131), we get a palindrome (4310330330134).
The spelling of 1310030030003 in words is "one trillion, three hundred ten billion, thirty million, thirty thousand, three".
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