Base | Representation |
---|---|
bin | 1011111010100010011011… |
… | …0011101010111000101011 |
3 | 1201101101011112011010100001 |
4 | 2332220212303222320223 |
5 | 3204113404120111021 |
6 | 43510110110123431 |
7 | 2521315452015025 |
oct | 276504663527053 |
9 | 51341145133301 |
10 | 13100301332011 |
11 | 41a089663a013 |
12 | 1576b144b0577 |
13 | 740478a4100a |
14 | 3340b50c5015 |
15 | 17ab80095091 |
hex | bea26ceae2b |
13100301332011 has 2 divisors, whose sum is σ = 13100301332012. Its totient is φ = 13100301332010.
The previous prime is 13100301331927. The next prime is 13100301332071. The reversal of 13100301332011 is 11023310300131.
It is a strong prime.
It is an emirp because it is prime and its reverse (11023310300131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13100301332011 - 211 = 13100301329963 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13100301332011.
It is not a weakly prime, because it can be changed into another prime (13100301332071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550150666005 + 6550150666006.
It is an arithmetic number, because the mean of its divisors is an integer number (6550150666006).
Almost surely, 213100301332011 is an apocalyptic number.
13100301332011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100301332011 is an equidigital number, since it uses as much as digits as its factorization.
13100301332011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13100301332011 its reverse (11023310300131), we get a palindrome (24123611632142).
The spelling of 13100301332011 in words is "thirteen trillion, one hundred billion, three hundred one million, three hundred thirty-two thousand, eleven".
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