13100402001441 has 8 divisors (see below), whose sum is σ = 17484971952960. Its totient is φ = 8724716692112.

The previous prime is 13100402001437. The next prime is 13100402001487. The reversal of 13100402001441 is 14410020400131.

13100402001441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13100402001441 - 2² = 13100402001437 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13100402071441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2221157106 + ... + 2221163003.

It is an arithmetic number, because the mean of its divisors is an integer number (2185621494120).

Almost surely, 2^{13100402001441} is an apocalyptic number.

It is an amenable number.

13100402001441 is a deficient number, since it is larger than the sum of its proper divisors (4384569951519).

13100402001441 is an equidigital number, since it uses as much as digits as its factorization.

13100402001441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4442321095.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 13100402001441 its reverse (14410020400131), we get a palindrome (27510422401572).

The spelling of 13100402001441 in words is "thirteen trillion, one hundred billion, four hundred two million, one thousand, four hundred forty-one".