Search a number
-
+
13101001322 = 26550500661
BaseRepresentation
bin11000011001110000…
…10110101001101010
31020211000211211020012
430030320112221222
5203312324020242
610003555531522
7642440450063
oct141470265152
936730754205
1013101001322
1156131a0222
1226575b9ba2
13130a2a61b6
148c3d3b56a
1551a253282
hex30ce16a6a

13101001322 has 4 divisors (see below), whose sum is σ = 19651501986. Its totient is φ = 6550500660.

The previous prime is 13101001321. The next prime is 13101001327. The reversal of 13101001322 is 22310010131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 22310010131 = 61365737871.

It can be written as a sum of positive squares in only one way, i.e., 8331855841 + 4769145481 = 91279^2 + 69059^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13101001297 and 13101001306.

It is not an unprimeable number, because it can be changed into a prime (13101001321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275250329 + ... + 3275250332.

Almost surely, 213101001322 is an apocalyptic number.

13101001322 is a deficient number, since it is larger than the sum of its proper divisors (6550500664).

13101001322 is an equidigital number, since it uses as much as digits as its factorization.

13101001322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6550500663.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13101001322 its reverse (22310010131), we get a palindrome (35411011453).

The spelling of 13101001322 in words is "thirteen billion, one hundred one million, one thousand, three hundred twenty-two".

Divisors: 1 2 6550500661 13101001322