131010109998353 has 2 divisors, whose sum is σ = 131010109998354. Its totient is φ = 131010109998352.

The previous prime is 131010109998283. The next prime is 131010109998389. The reversal of 131010109998353 is 353899901010131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125239891069969 + 5770218928384 = 11191063^2 + 2402128^2 .

It is a cyclic number.

It is not a de Polignac number, because 131010109998353 - 2¹⁴ = 131010109981969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131010109998295 and 131010109998304.

It is not a weakly prime, because it can be changed into another prime (131010109998553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505054999176 + 65505054999177.

It is an arithmetic number, because the mean of its divisors is an integer number (65505054999177).

Almost surely, 2^{131010109998353} is an apocalyptic number.

It is an amenable number.

131010109998353 is a deficient number, since it is larger than the sum of its proper divisors (1).

131010109998353 is an equidigital number, since it uses as much as digits as its factorization.

131010109998353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 787320, while the sum is 53.

The spelling of 131010109998353 in words is "one hundred thirty-one trillion, ten billion, one hundred nine million, nine hundred ninety-eight thousand, three hundred fifty-three".