131010121231441 has 4 divisors (see below), whose sum is σ = 133797570619392. Its totient is φ = 128222671843492.

The previous prime is 131010121231433. The next prime is 131010121231459. The reversal of 131010121231441 is 144132121010131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131010121231441 - 2³ = 131010121231433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131010121231421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1393724693905 + ... + 1393724693998.

It is an arithmetic number, because the mean of its divisors is an integer number (33449392654848).

Almost surely, 2^{131010121231441} is an apocalyptic number.

It is an amenable number.

131010121231441 is a deficient number, since it is larger than the sum of its proper divisors (2787449387951).

131010121231441 is an equidigital number, since it uses as much as digits as its factorization.

131010121231441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2787449387950.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 131010121231441 its reverse (144132121010131), we get a palindrome (275142242241572).

The spelling of 131010121231441 in words is "one hundred thirty-one trillion, ten billion, one hundred twenty-one million, two hundred thirty-one thousand, four hundred forty-one".