Base | Representation |
---|---|
bin | 11101110010011100111100… |
… | …011011110001001001000111 |
3 | 122011212110202010101122010121 |
4 | 131302130330123301021013 |
5 | 114132433300220421043 |
6 | 1142345203021202411 |
7 | 36411121606334020 |
oct | 3562347433611107 |
9 | 564773663348117 |
10 | 131010401342023 |
11 | 3882022113a355 |
12 | 1283a83a400407 |
13 | 58142c672c578 |
14 | 244cd19b9bc47 |
15 | 1022d34048ded |
hex | 77273c6f1247 |
131010401342023 has 16 divisors (see below), whose sum is σ = 149804821078336. Its totient is φ = 112235653071360.
The previous prime is 131010401341987. The next prime is 131010401342053. The reversal of 131010401342023 is 320243104010131.
It is not a de Polignac number, because 131010401342023 - 241 = 128811378086471 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131010401342053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 168940015 + ... + 169713727.
It is an arithmetic number, because the mean of its divisors is an integer number (9362801317396).
Almost surely, 2131010401342023 is an apocalyptic number.
131010401342023 is a deficient number, since it is larger than the sum of its proper divisors (18794419736313).
131010401342023 is a wasteful number, since it uses less digits than its factorization.
131010401342023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 786394.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 131010401342023 its reverse (320243104010131), we get a palindrome (451253505352154).
The spelling of 131010401342023 in words is "one hundred thirty-one trillion, ten billion, four hundred one million, three hundred forty-two thousand, twenty-three".
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