Base | Representation |
---|---|
bin | 11000011001110001… |
… | …00001010001101010 |
3 | 1020211000221000221001 |
4 | 30030320201101222 |
5 | 203312331413332 |
6 | 10004000505214 |
7 | 642441021004 |
oct | 141470412152 |
9 | 36730830831 |
10 | 13101044842 |
11 | 561321a996 |
12 | 265761b20a |
13 | 130a2bcc52 |
14 | 8c3d4d374 |
15 | 51a2610e7 |
hex | 30ce2146a |
13101044842 has 4 divisors (see below), whose sum is σ = 19651567266. Its totient is φ = 6550522420.
The previous prime is 13101044821. The next prime is 13101044851. The reversal of 13101044842 is 24844010131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12051867961 + 1049176881 = 109781^2 + 32391^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13101044842.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275261209 + ... + 3275261212.
Almost surely, 213101044842 is an apocalyptic number.
13101044842 is a deficient number, since it is larger than the sum of its proper divisors (6550522424).
13101044842 is an equidigital number, since it uses as much as digits as its factorization.
13101044842 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6550522423.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 13101044842 its reverse (24844010131), we get a palindrome (37945054973).
The spelling of 13101044842 in words is "thirteen billion, one hundred one million, forty-four thousand, eight hundred forty-two".
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