Base | Representation |
---|---|
bin | 111101000000011011… |
… | …1010011111101011011 |
3 | 110112011101022110220212 |
4 | 1322000313103331123 |
5 | 4121302304032303 |
6 | 140104032241335 |
7 | 12315401100434 |
oct | 1720067237533 |
9 | 415141273825 |
10 | 131011002203 |
11 | 5061a328044 |
12 | 214833a024b |
13 | c47b4947a3 |
14 | 64ab87c48b |
15 | 361b9b9ad8 |
hex | 1e80dd3f5b |
131011002203 has 2 divisors, whose sum is σ = 131011002204. Its totient is φ = 131011002202.
The previous prime is 131011002149. The next prime is 131011002211. The reversal of 131011002203 is 302200110131.
It is a strong prime.
It is an emirp because it is prime and its reverse (302200110131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131011002203 - 210 = 131011001179 is a prime.
It is not a weakly prime, because it can be changed into another prime (131011002223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505501101 + 65505501102.
It is an arithmetic number, because the mean of its divisors is an integer number (65505501102).
Almost surely, 2131011002203 is an apocalyptic number.
131011002203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011002203 is an equidigital number, since it uses as much as digits as its factorization.
131011002203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 131011002203 its reverse (302200110131), we get a palindrome (433211112334).
The spelling of 131011002203 in words is "one hundred thirty-one billion, eleven million, two thousand, two hundred three".
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