13101100313131 has 4 divisors (see below), whose sum is σ = 13379847128352. Its totient is φ = 12822353497912.

The previous prime is 13101100313117. The next prime is 13101100313237. The reversal of 13101100313131 is 13131300110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101100313131 - 2¹⁵ = 13101100280363 is a prime.

It is a super-2 number, since 2×13101100313131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101100313099 and 13101100313108.

It is not an unprimeable number, because it can be changed into a prime (13101100314131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139373407540 + ... + 139373407633.

It is an arithmetic number, because the mean of its divisors is an integer number (3344961782088).

Almost surely, 2^{13101100313131} is an apocalyptic number.

13101100313131 is a deficient number, since it is larger than the sum of its proper divisors (278746815221).

13101100313131 is an equidigital number, since it uses as much as digits as its factorization.

13101100313131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278746815220.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 13101100313131 its reverse (13131300110131), we get a palindrome (26232400423262).

The spelling of 13101100313131 in words is "thirteen trillion, one hundred one billion, one hundred million, three hundred thirteen thousand, one hundred thirty-one".