131011113341401 has 4 divisors (see below), whose sum is σ = 134057883419152. Its totient is φ = 127964343263652.

The previous prime is 131011113341399. The next prime is 131011113341443. The reversal of 131011113341401 is 104143311110131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131011113341401 - 2¹ = 131011113341399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131011113341701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1523385038811 + ... + 1523385038896.

It is an arithmetic number, because the mean of its divisors is an integer number (33514470854788).

Almost surely, 2^{131011113341401} is an apocalyptic number.

It is an amenable number.

131011113341401 is a deficient number, since it is larger than the sum of its proper divisors (3046770077751).

131011113341401 is an equidigital number, since it uses as much as digits as its factorization.

131011113341401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3046770077750.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 131011113341401 its reverse (104143311110131), we get a palindrome (235154424451532).

The spelling of 131011113341401 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirteen million, three hundred forty-one thousand, four hundred one".