13101112200201 has 4 divisors (see below), whose sum is σ = 17468149600272. Its totient is φ = 8734074800132.

The previous prime is 13101112200193. The next prime is 13101112200217. The reversal of 13101112200201 is 10200221110131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101112200201 - 2³ = 13101112200193 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13101112200301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183518700031 + ... + 2183518700036.

It is an arithmetic number, because the mean of its divisors is an integer number (4367037400068).

Almost surely, 2^{13101112200201} is an apocalyptic number.

It is an amenable number.

13101112200201 is a deficient number, since it is larger than the sum of its proper divisors (4367037400071).

13101112200201 is an equidigital number, since it uses as much as digits as its factorization.

13101112200201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4367037400070.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 13101112200201 its reverse (10200221110131), we get a palindrome (23301333310332).

The spelling of 13101112200201 in words is "thirteen trillion, one hundred one billion, one hundred twelve million, two hundred thousand, two hundred one".