Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …111011111111111011011011 |
3 | 122011212112121222202211210211 |
4 | 131302131213323333323123 |
5 | 114132441244042231413 |
6 | 1142345403252551551 |
7 | 36411145651201225 |
oct | 3562354773777333 |
9 | 564775558684724 |
10 | 131011131211483 |
11 | 38820566130056 |
12 | 1283aa029225b7 |
13 | 58143b19c93a3 |
14 | 244cd88aad415 |
15 | 1022d7816b83d |
hex | 772767effedb |
131011131211483 has 2 divisors, whose sum is σ = 131011131211484. Its totient is φ = 131011131211482.
The previous prime is 131011131211469. The next prime is 131011131211511. The reversal of 131011131211483 is 384112131110131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131011131211483 - 245 = 95826759122651 is a prime.
It is not a weakly prime, because it can be changed into another prime (131011131221483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505565605741 + 65505565605742.
It is an arithmetic number, because the mean of its divisors is an integer number (65505565605742).
Almost surely, 2131011131211483 is an apocalyptic number.
131011131211483 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011131211483 is an equidigital number, since it uses as much as digits as its factorization.
131011131211483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 31.
The spelling of 131011131211483 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty-one million, two hundred eleven thousand, four hundred eighty-three".
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