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131011131211483 is a prime number
BaseRepresentation
bin11101110010011101100111…
…111011111111111011011011
3122011212112121222202211210211
4131302131213323333323123
5114132441244042231413
61142345403252551551
736411145651201225
oct3562354773777333
9564775558684724
10131011131211483
1138820566130056
121283aa029225b7
1358143b19c93a3
14244cd88aad415
151022d7816b83d
hex772767effedb

131011131211483 has 2 divisors, whose sum is σ = 131011131211484. Its totient is φ = 131011131211482.

The previous prime is 131011131211469. The next prime is 131011131211511. The reversal of 131011131211483 is 384112131110131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131011131211483 - 245 = 95826759122651 is a prime.

It is not a weakly prime, because it can be changed into another prime (131011131221483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505565605741 + 65505565605742.

It is an arithmetic number, because the mean of its divisors is an integer number (65505565605742).

Almost surely, 2131011131211483 is an apocalyptic number.

131011131211483 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011131211483 is an equidigital number, since it uses as much as digits as its factorization.

131011131211483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 31.

The spelling of 131011131211483 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty-one million, two hundred eleven thousand, four hundred eighty-three".