Base | Representation |
---|---|
bin | 11101110010011101101000… |
… | …011111000110011001001001 |
3 | 122011212112122122002022220210 |
4 | 131302131220133012121021 |
5 | 114132441303421204001 |
6 | 1142345404222111333 |
7 | 36411146122333632 |
oct | 3562355037063111 |
9 | 564775578068823 |
10 | 131011140413001 |
11 | 38820570345312 |
12 | 1283aa05a1b549 |
13 | 58143b389b684 |
14 | 244cd89dc6889 |
15 | 1022d78d87dd6 |
hex | 7727687c6649 |
131011140413001 has 16 divisors (see below), whose sum is σ = 184957147566144. Its totient is φ = 82202960292864.
The previous prime is 131011140412993. The next prime is 131011140413003. The reversal of 131011140413001 is 100314041110131.
It is not a de Polignac number, because 131011140413001 - 23 = 131011140412993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131011140413003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57670465 + ... + 59899121.
It is an arithmetic number, because the mean of its divisors is an integer number (11559821722884).
Almost surely, 2131011140413001 is an apocalyptic number.
It is an amenable number.
131011140413001 is a deficient number, since it is larger than the sum of its proper divisors (53946007153143).
131011140413001 is a wasteful number, since it uses less digits than its factorization.
131011140413001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3381320.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 131011140413001 its reverse (100314041110131), we get a palindrome (231325181523132).
The spelling of 131011140413001 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty million, four hundred thirteen thousand, one".
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