131011142400331 has 2 divisors, whose sum is σ = 131011142400332. Its totient is φ = 131011142400330.

The previous prime is 131011142400289. The next prime is 131011142400353. The reversal of 131011142400331 is 133004241110131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131011142400331 - 2²¹ = 131011140303179 is a prime.

It is a super-2 number, since 2×131011142400331² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131011142400296 and 131011142400305.

It is not a weakly prime, because it can be changed into another prime (131011142400361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505571200165 + 65505571200166.

It is an arithmetic number, because the mean of its divisors is an integer number (65505571200166).

Almost surely, 2^{131011142400331} is an apocalyptic number.

131011142400331 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011142400331 is an equidigital number, since it uses as much as digits as its factorization.

131011142400331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 131011142400331 its reverse (133004241110131), we get a palindrome (264015383510462).

The spelling of 131011142400331 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-two million, four hundred thousand, three hundred thirty-one".