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13101120001 = 25035234167
BaseRepresentation
bin11000011001110001…
…10011101000000001
31020211001001212000201
430030320303220001
5203312341320001
610004002245201
7642441453064
oct141470635001
936731055021
1013101120001
115613271402
122657656801
13130a318218
148c3d6c8db
1551a278501
hex30ce33a01

13101120001 has 4 divisors (see below), whose sum is σ = 13106356672. Its totient is φ = 13095883332.

The previous prime is 13101119971. The next prime is 13101120017. The reversal of 13101120001 is 10002110131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101120001 - 213 = 13101111809 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13101120001.

It is not an unprimeable number, because it can be changed into a prime (13107120001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2614581 + ... + 2619586.

It is an arithmetic number, because the mean of its divisors is an integer number (3276589168).

Almost surely, 213101120001 is an apocalyptic number.

It is an amenable number.

13101120001 is a deficient number, since it is larger than the sum of its proper divisors (5236671).

13101120001 is an equidigital number, since it uses as much as digits as its factorization.

13101120001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5236670.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 13101120001 its reverse (10002110131), we get a palindrome (23103230132).

The spelling of 13101120001 in words is "thirteen billion, one hundred one million, one hundred twenty thousand, one".

Divisors: 1 2503 5234167 13101120001