Base | Representation |
---|---|
bin | 10011000100001000110… |
… | …001000010111010001011 |
3 | 11122020121222001100121121 |
4 | 103010020301002322023 |
5 | 132431102144144404 |
6 | 2441505053020111 |
7 | 163436541052414 |
oct | 23041061027213 |
9 | 4566558040547 |
10 | 1310112099979 |
11 | 465685142611 |
12 | 191aa9a84637 |
13 | 9670a0a3a57 |
14 | 475a456c80b |
15 | 2412ba77e54 |
hex | 13108c42e8b |
1310112099979 has 2 divisors, whose sum is σ = 1310112099980. Its totient is φ = 1310112099978.
The previous prime is 1310112099941. The next prime is 1310112100007. The reversal of 1310112099979 is 9799902110131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310112099979 - 27 = 1310112099851 is a prime.
It is a super-2 number, since 2×13101120999792 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310112099929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655056049989 + 655056049990.
It is an arithmetic number, because the mean of its divisors is an integer number (655056049990).
Almost surely, 21310112099979 is an apocalyptic number.
1310112099979 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310112099979 is an equidigital number, since it uses as much as digits as its factorization.
1310112099979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 275562, while the sum is 52.
The spelling of 1310112099979 in words is "one trillion, three hundred ten billion, one hundred twelve million, ninety-nine thousand, nine hundred seventy-nine".
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