Base | Representation |
---|---|
bin | 1011111010100101011110… |
… | …1010100100011101110011 |
3 | 1201101110021122120002120221 |
4 | 2332221113222210131303 |
5 | 3204122043440430003 |
6 | 43510323311113511 |
7 | 2521344664232056 |
oct | 276512752443563 |
9 | 51343248502527 |
10 | 13101121030003 |
11 | 41a1177304276 |
12 | 1577102b12897 |
13 | 7405797cca06 |
14 | 334151cdaa9d |
15 | 17abcc00d7bd |
hex | bea57aa4773 |
13101121030003 has 4 divisors (see below), whose sum is σ = 13102612684128. Its totient is φ = 13099629375880.
The previous prime is 13101121029959. The next prime is 13101121030037. The reversal of 13101121030003 is 30003012110131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13101121030003 - 221 = 13101118932851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13101121030103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 745813888 + ... + 745831453.
It is an arithmetic number, because the mean of its divisors is an integer number (3275653171032).
Almost surely, 213101121030003 is an apocalyptic number.
13101121030003 is a deficient number, since it is larger than the sum of its proper divisors (1491654125).
13101121030003 is an equidigital number, since it uses as much as digits as its factorization.
13101121030003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1491654124.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 13101121030003 its reverse (30003012110131), we get a palindrome (43104133140134).
The spelling of 13101121030003 in words is "thirteen trillion, one hundred one billion, one hundred twenty-one million, thirty thousand, three".
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