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13101122000233 is a prime number
BaseRepresentation
bin1011111010100101011110…
…1110010001010101101001
31201101110021201101101111101
42332221113232101111221
53204122044213001413
643510323344001401
72521345005412531
oct276512756212551
951343251341441
1013101122000233
1141a1177907213
121577103300261
13740579a7c507
143341520b04c1
1517abcc150edd
hexbea57b91569

13101122000233 has 2 divisors, whose sum is σ = 13101122000234. Its totient is φ = 13101122000232.

The previous prime is 13101122000209. The next prime is 13101122000249. The reversal of 13101122000233 is 33200022110131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7236573447744 + 5864548552489 = 2690088^2 + 2421683^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101122000233 - 213 = 13101121992041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13101122000233.

It is not a weakly prime, because it can be changed into another prime (13101122000273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550561000116 + 6550561000117.

It is an arithmetic number, because the mean of its divisors is an integer number (6550561000117).

Almost surely, 213101122000233 is an apocalyptic number.

It is an amenable number.

13101122000233 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101122000233 is an equidigital number, since it uses as much as digits as its factorization.

13101122000233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13101122000233 its reverse (33200022110131), we get a palindrome (46301144110364).

The spelling of 13101122000233 in words is "thirteen trillion, one hundred one billion, one hundred twenty-two million, two hundred thirty-three", and thus it is an aban number.