Base | Representation |
---|---|
bin | 1011111010100101011111… |
… | …0011010001011011011010 |
3 | 1201101110021210211222222020 |
4 | 2332221113303101123122 |
5 | 3204122100031430242 |
6 | 43510323432035310 |
7 | 2521345022513124 |
oct | 276512763213332 |
9 | 51343253758866 |
10 | 13101123311322 |
11 | 41a1178622262 |
12 | 1577103832b36 |
13 | 74057a11b1c7 |
14 | 334152332214 |
15 | 17abcc30e6ec |
hex | bea57cd16da |
13101123311322 has 64 divisors (see below), whose sum is σ = 27873565122816. Its totient is φ = 4095969912320.
The previous prime is 13101123311281. The next prime is 13101123311357. The reversal of 13101123311322 is 22311332110131.
It is a super-2 number, since 2×131011233113222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13101123311292 and 13101123311301.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12066988 + ... + 13107800.
It is an arithmetic number, because the mean of its divisors is an integer number (435524455044).
Almost surely, 213101123311322 is an apocalyptic number.
13101123311322 is an abundant number, since it is smaller than the sum of its proper divisors (14772441811494).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101123311322 is a wasteful number, since it uses less digits than its factorization.
13101123311322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1042615.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 13101123311322 its reverse (22311332110131), we get a palindrome (35412455421453).
The spelling of 13101123311322 in words is "thirteen trillion, one hundred one billion, one hundred twenty-three million, three hundred eleven thousand, three hundred twenty-two".
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