Base | Representation |
---|---|
bin | 1011111010100101011111… |
… | …0011010110010011001001 |
3 | 1201101110021210220000100011 |
4 | 2332221113303112103021 |
5 | 3204122100033100043 |
6 | 43510323432311521 |
7 | 2521345022625235 |
oct | 276512763262311 |
9 | 51343253800304 |
10 | 13101123331273 |
11 | 41a117863624a |
12 | 15771038425a1 |
13 | 74057a127303 |
14 | 3341523395c5 |
15 | 17abcc31559d |
hex | bea57cd64c9 |
13101123331273 has 2 divisors, whose sum is σ = 13101123331274. Its totient is φ = 13101123331272.
The previous prime is 13101123331267. The next prime is 13101123331339. The reversal of 13101123331273 is 37213332110131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12083389397689 + 1017733933584 = 3476117^2 + 1008828^2 .
It is a cyclic number.
It is not a de Polignac number, because 13101123331273 - 221 = 13101121234121 is a prime.
It is not a weakly prime, because it can be changed into another prime (13101123331223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550561665636 + 6550561665637.
It is an arithmetic number, because the mean of its divisors is an integer number (6550561665637).
Almost surely, 213101123331273 is an apocalyptic number.
It is an amenable number.
13101123331273 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101123331273 is an equidigital number, since it uses as much as digits as its factorization.
13101123331273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 31.
The spelling of 13101123331273 in words is "thirteen trillion, one hundred one billion, one hundred twenty-three million, three hundred thirty-one thousand, two hundred seventy-three".
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