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1310112400033 is a prime number
BaseRepresentation
bin10011000100001000110…
…010001100001010100001
311122020121222121121012201
4103010020302030022201
5132431102233300113
62441505103253201
7163436543442253
oct23041062141241
94566558547181
101310112400033
11465685327a98
12191aa9baa201
139670a17a4b8
14475a4609cd3
152412bad6cdd
hex13108c8c2a1

1310112400033 has 2 divisors, whose sum is σ = 1310112400034. Its totient is φ = 1310112400032.

The previous prime is 1310112399997. The next prime is 1310112400039. The reversal of 1310112400033 is 3300042110131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1145805398929 + 164307001104 = 1070423^2 + 405348^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310112400033 - 225 = 1310078845601 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310112400039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655056200016 + 655056200017.

It is an arithmetic number, because the mean of its divisors is an integer number (655056200017).

Almost surely, 21310112400033 is an apocalyptic number.

It is an amenable number.

1310112400033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310112400033 is an equidigital number, since it uses as much as digits as its factorization.

1310112400033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1310112400033 its reverse (3300042110131), we get a palindrome (4610154510164).

The spelling of 1310112400033 in words is "one trillion, three hundred ten billion, one hundred twelve million, four hundred thousand, thirty-three".