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131011344241321 is a prime number
BaseRepresentation
bin11101110010011101110100…
…101000101001001010101001
3122011212120011211121212210211
4131302131310220221022221
5114132442213111210241
61142345440342541121
736411154146004405
oct3562356450511251
9564776154555724
10131011344241321
1138820665402575
121283aa621377a1
135814416b9634b
14244cda90c4105
151022d8bbeb781
hex772774a292a9

131011344241321 has 2 divisors, whose sum is σ = 131011344241322. Its totient is φ = 131011344241320.

The previous prime is 131011344241307. The next prime is 131011344241343. The reversal of 131011344241321 is 123142443110131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118937804151321 + 12073540090000 = 10905861^2 + 3474700^2 .

It is an emirp because it is prime and its reverse (123142443110131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131011344241321 - 211 = 131011344239273 is a prime.

It is not a weakly prime, because it can be changed into another prime (131011344341321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505672120660 + 65505672120661.

It is an arithmetic number, because the mean of its divisors is an integer number (65505672120661).

Almost surely, 2131011344241321 is an apocalyptic number.

It is an amenable number.

131011344241321 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011344241321 is an equidigital number, since it uses as much as digits as its factorization.

131011344241321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 131011344241321 its reverse (123142443110131), we get a palindrome (254153787351452).

The spelling of 131011344241321 in words is "one hundred thirty-one trillion, eleven billion, three hundred forty-four million, two hundred forty-one thousand, three hundred twenty-one".