Base | Representation |
---|---|
bin | 1011111010100101100011… |
… | …1000000011010011011001 |
3 | 1201101110100001210000120221 |
4 | 2332221120320003103121 |
5 | 3204122114140411101 |
6 | 43510325314320041 |
7 | 2521345331666011 |
oct | 276513070032331 |
9 | 51343301700527 |
10 | 13101141341401 |
11 | 41a1187817553 |
12 | 1577109889021 |
13 | 740580a91aa9 |
14 | 3341548a6c41 |
15 | 17abcdbc1aa1 |
hex | bea58e034d9 |
13101141341401 has 2 divisors, whose sum is σ = 13101141341402. Its totient is φ = 13101141341400.
The previous prime is 13101141341389. The next prime is 13101141341411. The reversal of 13101141341401 is 10414314110131.
13101141341401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12832300128400 + 268841213001 = 3582220^2 + 518499^2 .
It is a cyclic number.
It is not a de Polignac number, because 13101141341401 - 223 = 13101132952793 is a prime.
It is not a weakly prime, because it can be changed into another prime (13101141341411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550570670700 + 6550570670701.
It is an arithmetic number, because the mean of its divisors is an integer number (6550570670701).
Almost surely, 213101141341401 is an apocalyptic number.
It is an amenable number.
13101141341401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101141341401 is an equidigital number, since it uses as much as digits as its factorization.
13101141341401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 13101141341401 its reverse (10414314110131), we get a palindrome (23515455451532).
The spelling of 13101141341401 in words is "thirteen trillion, one hundred one billion, one hundred forty-one million, three hundred forty-one thousand, four hundred one".
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