13101142030131 has 8 divisors (see below), whose sum is σ = 17585425544400. Its totient is φ = 8675476601312.

The previous prime is 13101142030099. The next prime is 13101142030153. The reversal of 13101142030131 is 13103024110131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13101142030131 - 2⁵ = 13101142030099 is a prime.

It is a super-2 number, since 2×13101142030131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13101142030098 and 13101142030107.

It is not an unprimeable number, because it can be changed into a prime (13101142030931) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14654520840 + ... + 14654521733.

It is an arithmetic number, because the mean of its divisors is an integer number (2198178193050).

Almost surely, 2^{13101142030131} is an apocalyptic number.

13101142030131 is a deficient number, since it is larger than the sum of its proper divisors (4484283514269).

13101142030131 is a wasteful number, since it uses less digits than its factorization.

13101142030131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29309042725.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 13101142030131 its reverse (13103024110131), we get a palindrome (26204166140262).

The spelling of 13101142030131 in words is "thirteen trillion, one hundred one billion, one hundred forty-two million, thirty thousand, one hundred thirty-one".