Base | Representation |
---|---|
bin | 11101110010011101111010… |
… | …100001111011011000010011 |
3 | 122011212120102201201200001211 |
4 | 131302131322201323120103 |
5 | 114132442413421103321 |
6 | 1142345454234440551 |
7 | 36411156456450130 |
oct | 3562357241733023 |
9 | 564776381650054 |
10 | 131011443144211 |
11 | 388207062147a3 |
12 | 1283aa8b293157 |
13 | 5814431514676 |
14 | 244cdb82ab587 |
15 | 1022d957360e1 |
hex | 77277a87b613 |
131011443144211 has 8 divisors (see below), whose sum is σ = 149727730692960. Its totient is φ = 112295247370368.
The previous prime is 131011443144191. The next prime is 131011443144227. The reversal of 131011443144211 is 112441344110131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131011443144211 - 215 = 131011443111443 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131011443141211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19857046 + ... + 25618843.
It is an arithmetic number, because the mean of its divisors is an integer number (18715966336620).
Almost surely, 2131011443144211 is an apocalyptic number.
131011443144211 is a deficient number, since it is larger than the sum of its proper divisors (18716287548749).
131011443144211 is an equidigital number, since it uses as much as digits as its factorization.
131011443144211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45887453.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 131011443144211 its reverse (112441344110131), we get a palindrome (243452787254342).
The spelling of 131011443144211 in words is "one hundred thirty-one trillion, eleven billion, four hundred forty-three million, one hundred forty-four thousand, two hundred eleven".
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