Base | Representation |
---|---|
bin | 11101110010011101111010… |
… | …100010001110111010011011 |
3 | 122011212120102201212201211002 |
4 | 131302131322202032322123 |
5 | 114132442413431133334 |
6 | 1142345454240255215 |
7 | 36411156460232315 |
oct | 3562357242167233 |
9 | 564776381781732 |
10 | 131011443224219 |
11 | 38820706269918 |
12 | 1283aa8b31150b |
13 | 5814431541bcc |
14 | 244cdb82cc7b5 |
15 | 1022d9574eb7e |
hex | 77277a88ee9b |
131011443224219 has 2 divisors, whose sum is σ = 131011443224220. Its totient is φ = 131011443224218.
The previous prime is 131011443224203. The next prime is 131011443224237. The reversal of 131011443224219 is 912422344110131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131011443224219 - 24 = 131011443224203 is a prime.
It is a super-2 number, since 2×1310114432242192 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (131011443214219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505721612109 + 65505721612110.
It is an arithmetic number, because the mean of its divisors is an integer number (65505721612110).
Almost surely, 2131011443224219 is an apocalyptic number.
131011443224219 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011443224219 is an equidigital number, since it uses as much as digits as its factorization.
131011443224219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 38.
The spelling of 131011443224219 in words is "one hundred thirty-one trillion, eleven billion, four hundred forty-three million, two hundred twenty-four thousand, two hundred nineteen".
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