Base | Representation |
---|---|
bin | 1011111010100101110001… |
… | …1000010100100011100011 |
3 | 1201101110111011101220120111 |
4 | 2332221130120110203203 |
5 | 3204122224213213243 |
6 | 43510335214352151 |
7 | 2521346644466062 |
oct | 276513430244343 |
9 | 51343434356514 |
10 | 13101200132323 |
11 | 41a1207a21a96 |
12 | 15771254bb657 |
13 | 740590007614 |
14 | 33415c60c1d9 |
15 | 17abd3e3639d |
hex | bea5c6148e3 |
13101200132323 has 2 divisors, whose sum is σ = 13101200132324. Its totient is φ = 13101200132322.
The previous prime is 13101200132309. The next prime is 13101200132347. The reversal of 13101200132323 is 32323100210131.
13101200132323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13101200132323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13101200132294 and 13101200132303.
It is not a weakly prime, because it can be changed into another prime (13101200132023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550600066161 + 6550600066162.
It is an arithmetic number, because the mean of its divisors is an integer number (6550600066162).
Almost surely, 213101200132323 is an apocalyptic number.
13101200132323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101200132323 is an equidigital number, since it uses as much as digits as its factorization.
13101200132323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13101200132323 its reverse (32323100210131), we get a palindrome (45424300342454).
The spelling of 13101200132323 in words is "thirteen trillion, one hundred one billion, two hundred million, one hundred thirty-two thousand, three hundred twenty-three".
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