131012143444131 has 16 divisors (see below), whose sum is σ = 175721724518400. Its totient is φ = 86822345582048.

The previous prime is 131012143444097. The next prime is 131012143444151. The reversal of 131012143444131 is 131444341210131.

It is a cyclic number.

It is not a de Polignac number, because 131012143444131 - 2¹⁰ = 131012143443107 is a prime.

It is a super-2 number, since 2×131012143444131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131012143444092 and 131012143444101.

It is not an unprimeable number, because it can be changed into a prime (131012143444151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42240291 + ... + 45235676.

It is an arithmetic number, because the mean of its divisors is an integer number (10982607782400).

Almost surely, 2^{131012143444131} is an apocalyptic number.

131012143444131 is a deficient number, since it is larger than the sum of its proper divisors (44709581074269).

131012143444131 is a wasteful number, since it uses less digits than its factorization.

131012143444131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87478938.

The product of its (nonzero) digits is 13824, while the sum is 33.

Adding to 131012143444131 its reverse (131444341210131), we get a palindrome (262456484654262).

The spelling of 131012143444131 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-three million, four hundred forty-four thousand, one hundred thirty-one".