Base | Representation |
---|---|
bin | 11101110010011110100111… |
… | …101010010111010011000001 |
3 | 122011212122101111111201021222 |
4 | 131302132213222113103001 |
5 | 114133000441241033213 |
6 | 1142350101323524425 |
7 | 36411214312436132 |
oct | 3562364752272301 |
9 | 564778344451258 |
10 | 131012200330433 |
11 | 38820a64672a34 |
12 | 1283b060989715 |
13 | 5814522357056 |
14 | 244d04aa8dc89 |
15 | 1022ddbe52808 |
hex | 7727a7a974c1 |
131012200330433 has 2 divisors, whose sum is σ = 131012200330434. Its totient is φ = 131012200330432.
The previous prime is 131012200330409. The next prime is 131012200330447. The reversal of 131012200330433 is 334033002210131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75578472313744 + 55433728016689 = 8693588^2 + 7445383^2 .
It is a cyclic number.
It is not a de Polignac number, because 131012200330433 - 244 = 113420014286017 is a prime.
It is not a weakly prime, because it can be changed into another prime (131012200330483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506100165216 + 65506100165217.
It is an arithmetic number, because the mean of its divisors is an integer number (65506100165217).
Almost surely, 2131012200330433 is an apocalyptic number.
It is an amenable number.
131012200330433 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012200330433 is an equidigital number, since it uses as much as digits as its factorization.
131012200330433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 131012200330433 its reverse (334033002210131), we get a palindrome (465045202540564).
The spelling of 131012200330433 in words is "one hundred thirty-one trillion, twelve billion, two hundred million, three hundred thirty thousand, four hundred thirty-three".
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