Base | Representation |
---|---|
bin | 11101110010011110101000… |
… | …011000011111101000100001 |
3 | 122011212122102100021002110021 |
4 | 131302132220120133220201 |
5 | 114133001002340020301 |
6 | 1142350102435033441 |
7 | 36411214520303044 |
oct | 3562365030375041 |
9 | 564778370232407 |
10 | 131012212423201 |
11 | 38820a7048245a |
12 | 1283b064a3b881 |
13 | 58145249cc335 |
14 | 244d04c51ac5b |
15 | 1022ddd0408a1 |
hex | 7727a861fa21 |
131012212423201 has 4 divisors (see below), whose sum is σ = 131021221047552. Its totient is φ = 131003203798852.
The previous prime is 131012212423193. The next prime is 131012212423259. The reversal of 131012212423201 is 102324212210131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131012212423201 - 23 = 131012212423193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131012212423271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4504290361 + ... + 4504319446.
It is an arithmetic number, because the mean of its divisors is an integer number (32755305261888).
Almost surely, 2131012212423201 is an apocalyptic number.
It is an amenable number.
131012212423201 is a deficient number, since it is larger than the sum of its proper divisors (9008624351).
131012212423201 is an equidigital number, since it uses as much as digits as its factorization.
131012212423201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9008624350.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 131012212423201 its reverse (102324212210131), we get a palindrome (233336424633332).
The spelling of 131012212423201 in words is "one hundred thirty-one trillion, twelve billion, two hundred twelve million, four hundred twenty-three thousand, two hundred one".
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