Base | Representation |
---|---|
bin | 11101110010011110101000… |
… | …111010101111010110000001 |
3 | 122011212122102222011011220221 |
4 | 131302132220322233112001 |
5 | 114133001012134303244 |
6 | 1142350103355303041 |
7 | 36411214656512554 |
oct | 3562365072572601 |
9 | 564778388134827 |
10 | 131012221400449 |
11 | 38820a75554174 |
12 | 1283b067a4aa81 |
13 | 581452682350c |
14 | 244d04d7b669b |
15 | 1022dddc15784 |
hex | 7727a8eaf581 |
131012221400449 has 2 divisors, whose sum is σ = 131012221400450. Its totient is φ = 131012221400448.
The previous prime is 131012221400387. The next prime is 131012221400479. The reversal of 131012221400449 is 944004122210131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 122409175121424 + 8603046279025 = 11063868^2 + 2933095^2 .
It is a cyclic number.
It is not a de Polignac number, because 131012221400449 - 29 = 131012221399937 is a prime.
It is not a weakly prime, because it can be changed into another prime (131012221400479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506110700224 + 65506110700225.
It is an arithmetic number, because the mean of its divisors is an integer number (65506110700225).
Almost surely, 2131012221400449 is an apocalyptic number.
It is an amenable number.
131012221400449 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012221400449 is an equidigital number, since it uses as much as digits as its factorization.
131012221400449 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 34.
The spelling of 131012221400449 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-one million, four hundred thousand, four hundred forty-nine".
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