Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000001110001011011111011 |
3 | 122011212122110002121211211121 |
4 | 131302132221001301123323 |
5 | 114133001013122302102 |
6 | 1142350103503010111 |
7 | 36411215011261456 |
oct | 3562365101613373 |
9 | 564778402554747 |
10 | 131012223244027 |
11 | 38820a765a3294 |
12 | 1283b068599937 |
13 | 581452701a6a8 |
14 | 244d04db3649d |
15 | 1022ddde7bb37 |
hex | 7727a90716fb |
131012223244027 has 2 divisors, whose sum is σ = 131012223244028. Its totient is φ = 131012223244026.
The previous prime is 131012223243989. The next prime is 131012223244057. The reversal of 131012223244027 is 720442322210131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131012223244027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131012223243983 and 131012223244001.
It is not a weakly prime, because it can be changed into another prime (131012223244057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506111622013 + 65506111622014.
It is an arithmetic number, because the mean of its divisors is an integer number (65506111622014).
Almost surely, 2131012223244027 is an apocalyptic number.
131012223244027 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012223244027 is an equidigital number, since it uses as much as digits as its factorization.
131012223244027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 131012223244027 its reverse (720442322210131), we get a palindrome (851454545454158).
The spelling of 131012223244027 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-three million, two hundred forty-four thousand, twenty-seven".
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