131012224103041 has 4 divisors (see below), whose sum is σ = 131012247504832. Its totient is φ = 131012200701252.

The previous prime is 131012224103023. The next prime is 131012224103053. The reversal of 131012224103041 is 140301422210131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131012224103041 - 2⁵ = 131012224103009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131012224102997 and 131012224103015.

It is not an unprimeable number, because it can be changed into a prime (131012224103021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2207356 + ... + 16336978.

It is an arithmetic number, because the mean of its divisors is an integer number (32753061876208).

Almost surely, 2^{131012224103041} is an apocalyptic number.

It is an amenable number.

131012224103041 is a deficient number, since it is larger than the sum of its proper divisors (23401791).

131012224103041 is an equidigital number, since it uses as much as digits as its factorization.

131012224103041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23401790.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131012224103041 its reverse (140301422210131), we get a palindrome (271313646313172).

The spelling of 131012224103041 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, one hundred three thousand, forty-one".