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131012224134443 = 342241382806923
BaseRepresentation
bin11101110010011110101001…
…000101001010110100101011
3122011212122110011022002020222
4131302132221011022310223
5114133001013334300233
61142350103534040255
736411215021660441
oct3562365105126453
9564778404262228
10131012224134443
1138820a77051273
121283b06894908b
13581452726ca72
14244d04dcc8b91
151022dde0a5898
hex7727a914ad2b

131012224134443 has 4 divisors (see below), whose sum is σ = 131012607283608. Its totient is φ = 131011840985280.

The previous prime is 131012224134431. The next prime is 131012224134469. The reversal of 131012224134443 is 344431422210131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131012224134443 - 214 = 131012224118059 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131012224134403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191061221 + ... + 191745702.

It is an arithmetic number, because the mean of its divisors is an integer number (32753151820902).

Almost surely, 2131012224134443 is an apocalyptic number.

131012224134443 is a deficient number, since it is larger than the sum of its proper divisors (383149165).

131012224134443 is an equidigital number, since it uses as much as digits as its factorization.

131012224134443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 383149164.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 131012224134443 its reverse (344431422210131), we get a palindrome (475443646344574).

The spelling of 131012224134443 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, one hundred thirty-four thousand, four hundred forty-three".

Divisors: 1 342241 382806923 131012224134443