Base | Representation |
---|---|
bin | 1011111010100101111011… |
… | …0010011110000010110001 |
3 | 1201101110120222102220100112 |
4 | 2332221132302132002301 |
5 | 3204122320034310421 |
6 | 43510343220431105 |
7 | 2521350645116510 |
oct | 276513662360261 |
9 | 51343528386315 |
10 | 13101240541361 |
11 | 41a1228811995 |
12 | 1577136b48495 |
13 | 7405984b53ab |
14 | 334163b2a677 |
15 | 17abd776945b |
hex | bea5ec9e0b1 |
13101240541361 has 8 divisors (see below), whose sum is σ = 14976186285504. Its totient is φ = 11227129785360.
The previous prime is 13101240541309. The next prime is 13101240541369. The reversal of 13101240541361 is 16314504210131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13101240541361 - 210 = 13101240540337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13101240541369) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 208713410 + ... + 208776171.
It is an arithmetic number, because the mean of its divisors is an integer number (1872023285688).
Almost surely, 213101240541361 is an apocalyptic number.
It is an amenable number.
13101240541361 is a deficient number, since it is larger than the sum of its proper divisors (1874945744143).
13101240541361 is an equidigital number, since it uses as much as digits as its factorization.
13101240541361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 417494071.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 13101240541361 its reverse (16314504210131), we get a palindrome (29415744751492).
The spelling of 13101240541361 in words is "thirteen trillion, one hundred one billion, two hundred forty million, five hundred forty-one thousand, three hundred sixty-one".
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