Base | Representation |
---|---|
bin | 111101000000011110… |
… | …1010001000111101001 |
3 | 110112011111020210112012 |
4 | 1322000331101013221 |
5 | 4121303204012213 |
6 | 140104125525305 |
7 | 12315420262223 |
oct | 1720075210751 |
9 | 415144223465 |
10 | 131012563433 |
11 | 506201a4014 |
12 | 21483a13835 |
13 | c47b8c02ab |
14 | 64abb67413 |
15 | 361bbc74a8 |
hex | 1e80f511e9 |
131012563433 has 2 divisors, whose sum is σ = 131012563434. Its totient is φ = 131012563432.
The previous prime is 131012563397. The next prime is 131012563439. The reversal of 131012563433 is 334365210131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125593689664 + 5418873769 = 354392^2 + 73613^2 .
It is a cyclic number.
It is not a de Polignac number, because 131012563433 - 228 = 130744127977 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131012563433.
It is not a weakly prime, because it can be changed into another prime (131012563439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506281716 + 65506281717.
It is an arithmetic number, because the mean of its divisors is an integer number (65506281717).
Almost surely, 2131012563433 is an apocalyptic number.
It is an amenable number.
131012563433 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012563433 is an equidigital number, since it uses as much as digits as its factorization.
131012563433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 32.
Adding to 131012563433 its reverse (334365210131), we get a palindrome (465377773564).
The spelling of 131012563433 in words is "one hundred thirty-one billion, twelve million, five hundred sixty-three thousand, four hundred thirty-three".
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