Base | Representation |
---|---|
bin | 1011111010100110001001… |
… | …1100111101110001001001 |
3 | 1201101110202021002222120221 |
4 | 2332221202130331301021 |
5 | 3204122431303404001 |
6 | 43510353254150041 |
7 | 2521352322453226 |
oct | 276514234756111 |
9 | 51343667088527 |
10 | 13101302013001 |
11 | 41a125a4884a4 |
12 | 1577153652321 |
13 | 7405a8159147 |
14 | 33416bd6c94d |
15 | 17abdcd5d1a1 |
hex | bea6273dc49 |
13101302013001 has 2 divisors, whose sum is σ = 13101302013002. Its totient is φ = 13101302013000.
The previous prime is 13101302012993. The next prime is 13101302013029. The reversal of 13101302013001 is 10031020310131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9331491453001 + 3769810560000 = 3054749^2 + 1941600^2 .
It is a cyclic number.
It is not a de Polignac number, because 13101302013001 - 23 = 13101302012993 is a prime.
It is a super-2 number, since 2×131013020130012 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13101302013031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550651006500 + 6550651006501.
It is an arithmetic number, because the mean of its divisors is an integer number (6550651006501).
Almost surely, 213101302013001 is an apocalyptic number.
It is an amenable number.
13101302013001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101302013001 is an equidigital number, since it uses as much as digits as its factorization.
13101302013001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 13101302013001 its reverse (10031020310131), we get a palindrome (23132322323132).
The spelling of 13101302013001 in words is "thirteen trillion, one hundred one billion, three hundred two million, thirteen thousand, one".
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