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13101302013001 is a prime number
BaseRepresentation
bin1011111010100110001001…
…1100111101110001001001
31201101110202021002222120221
42332221202130331301021
53204122431303404001
643510353254150041
72521352322453226
oct276514234756111
951343667088527
1013101302013001
1141a125a4884a4
121577153652321
137405a8159147
1433416bd6c94d
1517abdcd5d1a1
hexbea6273dc49

13101302013001 has 2 divisors, whose sum is σ = 13101302013002. Its totient is φ = 13101302013000.

The previous prime is 13101302012993. The next prime is 13101302013029. The reversal of 13101302013001 is 10031020310131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9331491453001 + 3769810560000 = 3054749^2 + 1941600^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101302013001 - 23 = 13101302012993 is a prime.

It is a super-2 number, since 2×131013020130012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13101302013031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550651006500 + 6550651006501.

It is an arithmetic number, because the mean of its divisors is an integer number (6550651006501).

Almost surely, 213101302013001 is an apocalyptic number.

It is an amenable number.

13101302013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101302013001 is an equidigital number, since it uses as much as digits as its factorization.

13101302013001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13101302013001 its reverse (10031020310131), we get a palindrome (23132322323132).

The spelling of 13101302013001 in words is "thirteen trillion, one hundred one billion, three hundred two million, thirteen thousand, one".