Base | Representation |
---|---|
bin | 11000011001110011… |
… | …00000000111011010 |
3 | 1020211001102010000002 |
4 | 30030321200013122 |
5 | 203312413132414 |
6 | 10004010213002 |
7 | 642443142266 |
oct | 141471400732 |
9 | 36731363002 |
10 | 13101302234 |
11 | 5613386309 |
12 | 2657724162 |
13 | 130a380157 |
14 | 8c3db90a6 |
15 | 51a2b24de |
hex | 30ce601da |
13101302234 has 4 divisors (see below), whose sum is σ = 19651953354. Its totient is φ = 6550651116.
The previous prime is 13101302231. The next prime is 13101302257. The reversal of 13101302234 is 43220310131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43220310131 = 13691 ⋅3156841.
It can be written as a sum of positive squares in only one way, i.e., 6889498009 + 6211804225 = 83003^2 + 78815^2 .
It is a super-3 number, since 3×131013022343 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (13101302231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275325557 + ... + 3275325560.
Almost surely, 213101302234 is an apocalyptic number.
13101302234 is a deficient number, since it is larger than the sum of its proper divisors (6550651120).
13101302234 is an equidigital number, since it uses as much as digits as its factorization.
13101302234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6550651119.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13101302234 its reverse (43220310131), we get a palindrome (56321612365).
The spelling of 13101302234 in words is "thirteen billion, one hundred one million, three hundred two thousand, two hundred thirty-four".
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