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13101312230233 is a prime number
BaseRepresentation
bin1011111010100110001100…
…0011111100001101011001
31201101110202222100001222221
42332221203003330031121
53204122441412331413
643510354301144041
72521352505346123
oct276514303741531
951343688301887
1013101312230233
1141a1265226897
121577156b5b021
137405aa2c5846
1433416d46c213
1517abddbca68d
hexbea630fc359

13101312230233 has 2 divisors, whose sum is σ = 13101312230234. Its totient is φ = 13101312230232.

The previous prime is 13101312230213. The next prime is 13101312230249. The reversal of 13101312230233 is 33203221310131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6800996368384 + 6300315861849 = 2607872^2 + 2510043^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101312230233 - 221 = 13101310133081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13101312230198 and 13101312230207.

It is not a weakly prime, because it can be changed into another prime (13101312230213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550656115116 + 6550656115117.

It is an arithmetic number, because the mean of its divisors is an integer number (6550656115117).

Almost surely, 213101312230233 is an apocalyptic number.

It is an amenable number.

13101312230233 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101312230233 is an equidigital number, since it uses as much as digits as its factorization.

13101312230233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13101312230233 its reverse (33203221310131), we get a palindrome (46304533540364).

The spelling of 13101312230233 in words is "thirteen trillion, one hundred one billion, three hundred twelve million, two hundred thirty thousand, two hundred thirty-three".