Base | Representation |
---|---|
bin | 10011000100001010000… |
… | …000111001000110011011 |
3 | 11122020200102102210000120 |
4 | 103010022000321012123 |
5 | 132431123024000243 |
6 | 2441511121404323 |
7 | 163440214010634 |
oct | 23041200710633 |
9 | 4566612383016 |
10 | 1310133031323 |
11 | 465695a39646 |
12 | 191ab4a996a3 |
13 | 9671152206c |
14 | 475a725a88b |
15 | 2412d80ec83 |
hex | 1310a03919b |
1310133031323 has 4 divisors (see below), whose sum is σ = 1746844041768. Its totient is φ = 873422020880.
The previous prime is 1310133031303. The next prime is 1310133031331. The reversal of 1310133031323 is 3231303310131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310133031323 - 224 = 1310116254107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310133031293 and 1310133031302.
It is not an unprimeable number, because it can be changed into a prime (1310133031303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218355505218 + ... + 218355505223.
It is an arithmetic number, because the mean of its divisors is an integer number (436711010442).
Almost surely, 21310133031323 is an apocalyptic number.
1310133031323 is a deficient number, since it is larger than the sum of its proper divisors (436711010445).
1310133031323 is an equidigital number, since it uses as much as digits as its factorization.
1310133031323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436711010444.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 1310133031323 its reverse (3231303310131), we get a palindrome (4541436341454).
The spelling of 1310133031323 in words is "one trillion, three hundred ten billion, one hundred thirty-three million, thirty-one thousand, three hundred twenty-three".
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