131014011481 has 2 divisors, whose sum is σ = 131014011482. Its totient is φ = 131014011480.

The previous prime is 131014011463. The next prime is 131014011523. The reversal of 131014011481 is 184110410131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127531123225 + 3482888256 = 357115^2 + 59016^2 .

It is a cyclic number.

It is not a de Polignac number, because 131014011481 - 2⁵ = 131014011449 is a prime.

It is a super-2 number, since 2×131014011481² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131014011431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65507005740 + 65507005741.

It is an arithmetic number, because the mean of its divisors is an integer number (65507005741).

Almost surely, 2^131014011481 is an apocalyptic number.

It is an amenable number.

131014011481 is a deficient number, since it is larger than the sum of its proper divisors (1).

131014011481 is an equidigital number, since it uses as much as digits as its factorization.

131014011481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 25.

The spelling of 131014011481 in words is "one hundred thirty-one billion, fourteen million, eleven thousand, four hundred eighty-one".