1310140244443 has 4 divisors (see below), whose sum is σ = 1310303225520. Its totient is φ = 1309977263368.

The previous prime is 1310140244419. The next prime is 1310140244467. The reversal of 1310140244443 is 3444420410131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1310140244419) and next prime (1310140244467).

It is a cyclic number.

It is not a de Polignac number, because 1310140244443 - 2⁹ = 1310140243931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310140244473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81478480 + ... + 81494557.

It is an arithmetic number, because the mean of its divisors is an integer number (327575806380).

Almost surely, 2^{1310140244443} is an apocalyptic number.

1310140244443 is a deficient number, since it is larger than the sum of its proper divisors (162981077).

1310140244443 is an equidigital number, since it uses as much as digits as its factorization.

1310140244443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162981076.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1310140244443 its reverse (3444420410131), we get a palindrome (4754560654574).

The spelling of 1310140244443 in words is "one trillion, three hundred ten billion, one hundred forty million, two hundred forty-four thousand, four hundred forty-three".