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1310200212011 = 4470129310311
BaseRepresentation
bin10011000100001110000…
…001001010101000101011
311122020212002211220121012
4103010032001022220223
5132431242223241021
62441521521334135
7163441661022665
oct23041601125053
94566762756535
101310200212011
1146571a954479
12191b1349734b
1396722414552
14475b2147535
152413468035b
hex1310e04aa2b

1310200212011 has 4 divisors (see below), whose sum is σ = 1310229567024. Its totient is φ = 1310170857000.

The previous prime is 1310200211993. The next prime is 1310200212029. The reversal of 1310200212011 is 1102120020131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1310200211993) and next prime (1310200212029).

It is a cyclic number.

It is not a de Polignac number, because 1310200212011 - 218 = 1310199949867 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310200212031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14610455 + ... + 14699856.

It is an arithmetic number, because the mean of its divisors is an integer number (327557391756).

Almost surely, 21310200212011 is an apocalyptic number.

1310200212011 is a deficient number, since it is larger than the sum of its proper divisors (29355013).

1310200212011 is an equidigital number, since it uses as much as digits as its factorization.

1310200212011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29355012.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 1310200212011 its reverse (1102120020131), we get a palindrome (2412320232142).

The spelling of 1310200212011 in words is "one trillion, three hundred ten billion, two hundred million, two hundred twelve thousand, eleven".

Divisors: 1 44701 29310311 1310200212011