Base | Representation |
---|---|
bin | 10011000100001110000… |
… | …001001010101000101011 |
3 | 11122020212002211220121012 |
4 | 103010032001022220223 |
5 | 132431242223241021 |
6 | 2441521521334135 |
7 | 163441661022665 |
oct | 23041601125053 |
9 | 4566762756535 |
10 | 1310200212011 |
11 | 46571a954479 |
12 | 191b1349734b |
13 | 96722414552 |
14 | 475b2147535 |
15 | 2413468035b |
hex | 1310e04aa2b |
1310200212011 has 4 divisors (see below), whose sum is σ = 1310229567024. Its totient is φ = 1310170857000.
The previous prime is 1310200211993. The next prime is 1310200212029. The reversal of 1310200212011 is 1102120020131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (1310200211993) and next prime (1310200212029).
It is a cyclic number.
It is not a de Polignac number, because 1310200212011 - 218 = 1310199949867 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1310200212031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14610455 + ... + 14699856.
It is an arithmetic number, because the mean of its divisors is an integer number (327557391756).
Almost surely, 21310200212011 is an apocalyptic number.
1310200212011 is a deficient number, since it is larger than the sum of its proper divisors (29355013).
1310200212011 is an equidigital number, since it uses as much as digits as its factorization.
1310200212011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29355012.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1310200212011 its reverse (1102120020131), we get a palindrome (2412320232142).
The spelling of 1310200212011 in words is "one trillion, three hundred ten billion, two hundred million, two hundred twelve thousand, eleven".
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